0=16t^2+85t+10

Solution for 0=16t^2+85t+10 equation:

0=16t^2+85t+10

We move all terms to the left:

0-(16t^2+85t+10)=0

We add all the numbers together, and all the variables

-(16t^2+85t+10)=0

We get rid of parentheses

-16t^2-85t-10=0

a = -16; b = -85; c = -10;
Δ = b2-4ac
Δ = -852-4·(-16)·(-10)
Δ = 6585
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-85)-\sqrt{6585}}{2*-16}=\frac{85-\sqrt{6585}}{-32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-85)+\sqrt{6585}}{2*-16}=\frac{85+\sqrt{6585}}{-32}
$